Find the output of the code: #include <stdio.h> #define x 9+2/43-24+(5-4)3 void main(){ int i,y; y=6+33/5; i=x*x+y; printf("%d",i); }

Find the output of the code:

#include <stdio.h>
#define x 9+2/4*3-2*4+(5-4)*3
void main(){
    int i,y;
    y=6+3*3/5;
    i=x*x+y;
    printf("%d",i);
}

From the DESCO Sub-Assistant Engineer (CSE) 2019 – Written (BUET) exam, question 4 of 10.

Find the output of the code: #include <stdio.h> #define x 9+2/4*3-2*4+(5-4)*3 void main(){ int i,y; y=6+3*3/5; i=x*x+y; printf("%d",i); }