Solve for x: \log_2(x + 2) - \log_2(x - 1) = 2

Solve for x: \(\log_2(x + 2) - \log_2(x - 1) = 2\)

A) x = 1
B) x = 2
C) x = 3
D) x = 4

From the SPCBL Assistant Manager (General) November 2026 – Preliminary (BSCS) exam, question 63 of 100.

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