Let the numbers be \(x\) and \(x + 2\).
\(x(x + 2) = 143 \Rightarrow x^2 + 2x - 143 = 0 \Rightarrow (x + 13)(x - 11) = 0\)
\(x = 11\) (x = −13 is rejected, as the numbers are positive).
The numbers are 11 and 13. Check: 11 × 13 = 143.
— rhs
The product of two consecutive positive odd numbers is 143. Find the numbers.
From the Combined Bank Assistant Programmer (CSE) October 2026 – Written (BIBM) exam, question 17 of 21.
Let the numbers be \(x\) and \(x + 2\).
\(x(x + 2) = 143 \Rightarrow x^2 + 2x - 143 = 0 \Rightarrow (x + 13)(x - 11) = 0\)
\(x = 11\) (x = −13 is rejected, as the numbers are positive).
The numbers are 11 and 13. Check: 11 × 13 = 143.
— rhs